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DaysInAnyMonth

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Submitted on: 2/1/2001 8:49:56 PM
By: Joe McDonnell 
Level: Beginner
User Rating: By 3 Users
Compatibility: ASP (Active Server Pages), VbScript (browser/client side)
Views: 21173
 
     Return the number of days in any month including leap years
 
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'**************************************
' Name: DaysInAnyMonth
' Description:Return the number of days in any month including leap years
' By: Joe McDonnell
'
' Inputs:IntMonth .... number of month
IntYear ..... 4 figure year or zero for current year
'
' Returns:days in month
'
' Assumes:A year is a leap year if:
It is divisible by 4 but not by 100, or
It is divisible by 400.
'
'This code is copyrighted and has' limited warranties.Please see http://www.Planet-Source-Code.com/vb/scripts/ShowCode.asp?txtCodeId=6477&lngWId=4'for details.'**************************************

Function DaysInAnyMonth(intMonth, IntYear)
If IntYear = 0 Then
IntYear = Year(Now())
End If
Select Case (intMonth)
Case 9, 4, 6, 11
DaysInAnyMonth = 30
Case 2
If (IntYear Mod 4 = 0) And (IntYear Mod 100 <> 0) Or (IntYear Mod 400 = 0) Then
DaysInAnyMonth = 29
Else
DaysInAnyMonth = 28
End If
Case Else
DaysInAnyMonth = 31
End Select
End Function


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Other User Comments

3/29/2001 2:09:22 AMJeffgueldre@hotmail.com

I propose an alternative code :
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4/17/2001 11:03:14 AMJeff

DaysInAnyMonth=dateserial(IntYear, intMonth+1,0)

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9/3/2001 10:09:46 AMdcoragem

Remenber, day 0 of the Month is the last day of the previous month.

DaysInAnyMonth = Day(TheYear, TheMonth + 1, 0)

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9/3/2001 3:36:37 PMNery

DaysInAnyMonth = Day(DateSerial(Year, Month + 1, 0))
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10/17/2002 12:35:58 AMCharles Chadwick

Day(DateAdd("d", -1, currentMonth + 1 & "/01/" & currentYear))
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