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nth largest/smallest from a table
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Email
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| Submitted on: |
12/18/2001 12:22:58 AM |
| By: |
MuraliKrishna Vedagiri
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| Level: |
Intermediate |
| User Rating: |
By 5 Users |
| Compatibility: |
SQL Server 7.0, SQL Server 6.5 and earlier, Informix
, Oracle, Other |
| Views: |
20467 |
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To find Nth largest and Smallest 'value'(Numbers) from a Table.
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code:
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--**************************************
-- Name: nth largest/smallest from a table
-- Description:To find Nth largest and Smallest 'value'(Numbers) from a Table.
-- By: MuraliKrishna Vedagiri
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-- Inputs:The N: The index of the largest/smallest number.
--
-- Returns:Largest / Smallest
--
-- Assumes:SImple SQL knowledge
--
--This code is copyrighted and has-- limited warranties.Please see http://www.Planet-Source-Code.com/vb/scripts/ShowCode.asp?txtCodeId=374&lngWId=5--for details.--**************************************
select a.itemid from item a where (n-1) = (select count(*) from item b where b.itemid > a.itemid)
/** By changing > to < you can get Smallest Number **
** If you want to find the 4th largest, then 4-1 =3 in place of (n-1)/
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Your Vote
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Other User Comments
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 12/18/2001 6:19:50 AM: James Travis
This is great, works as promised.
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12/18/2001 9:28:45 AM: kevin
why can't you just use...
SELECT TOP n [PERCENT] a, b FROM myTable
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12/18/2001 9:51:29 AM: Srinivas VM
Perfect and neat.
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6/13/2002 7:29:28 AM: Sushil Daga
Wonderful. but will fail if there are multiple records with the same value, instead use:
SELECT a.itemid FROM item a WHERE (n-1) = (SELECT COUNT(distinct b.itemid) FROM item b WHERE b.itemid > a.itemid)
if no duplicate values then use this for better performance:
SELECT a.itemid FROM item a WHERE (n-1) = (SELECT COUNT('x') FROM item b WHERE b.itemid > a.itemid)
Please note: My solution will work perfectly on oracle.
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6/27/2002 12:36:07 PM: Roger
excelent
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7/1/2002 4:44:51 PM: vinnie
why not use ">=" in
"where b.itemid > a.itemid" so that you don't need to subtract 1 from n?
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