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Precise Calculation of Pi
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Email
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| Submitted on: |
4/15/2000 3:44:17 PM |
| By: |
Eli
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| Level: |
Beginner |
| User Rating: |
By 4 Users |
| Compatibility: |
C++ (general) |
| Views: |
31336 |
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This code calculates an estimated value of Pi using the Leibnitz series (which is basically a power series expansion of a trigonometric function which allows to estimate Pi very well)
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//**************************************
//INCLUDE files for :Precise Calculation of Pi
//**************************************
iostream.h
math.h | |
code:
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//**************************************
// Name: Precise Calculation of Pi
// Description:This code calculates an estimated value of Pi using the Leibnitz series (which is basically a power series expansion of a trigonometric function which allows to estimate Pi very well)
// By: Eli
//
// Inputs:n/a
//
// Returns:Prints the estimated value of Pi
//
// Assumes:n/a
//
// Side Effects:n/a
//
//This code is copyrighted and has// limited warranties.Please see http://www.Planet-Source-Code.com/vb/scripts/ShowCode.asp?txtCodeId=360&lngWId=3//for details.//**************************************
#include <iostream.h>
#include <math.h>
#define NUM_OF_ELEMENTS 20000
int main()
{
double pi = 0;
// Calculating pi/4
for (long int n = 1; n <= NUM_OF_ELEMENTS; n++)
{
pi += (double) pow(-1, n+1)/(2*n-1);
}
// Calculating pi
pi *= 4;
cout << "Estimated PI value (" << NUM_OF_ELEMENTS << " elements of Leibnitz series): "<< pi;
return 0;
}
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Other 5 submission(s) by this author
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Other User Comments
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 4/15/2000 8:58:32 PM: Frank Chiu
Good application of the formula in C language.
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4/24/2000 6:21:30 PM: Ultimatum
I've been looking for this kind of code =) Learned a formula for finding more numbers in repeating decimals in 7th grade... can't remember it... In English, what's the formula?
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4/25/2000 3:36:09 PM: Eli
Pi/4 = sum (n from 9 to infinity) of ((-1)^(n-1))/(2*n-1)
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4/25/2000 3:37:42 PM: Eli
Oops, n from 0 to infinity, of course !
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