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aren't you always going to be stuck in this loop because you are constantly reseting the value of $x to 0 ?? (If this comment was disrespectful, please report it.)
No Travis, because you're saying that ("X will start at 0, do the task and add one to X. Keep doing that until X=99 or 100") (If this comment was disrespectful, please report it.)
The construct is not complete without the closing brace, and Brandon, it finishes when $x is greater than 100. (If this comment was disrespectful, please report it.)
LOL @ your comment Joseph! the loop will run! have u ever coded in perl? if not just run this perl progie: #!/usr/bin/perl for($x=0;$x<=100;$x++){ print "\n$x"; } by doing this u will c that the loop stops when $x = 100, it is a shame having ppl who don't even know what they r saying posting comments, plz go learn b4 saying anything (the code will print 101 lines each line contains a # from 0 to 100). Bleh. Laterz (If this comment was disrespectful, please report it.)
Technically Bruno the loop stops when $x equals 101. The post incremental operator ($x++) increments $x after execution of code contained within loop and then the loop test ($x<=100) returns false i.e $x is NOT less than or equal to 100, thus ending the looping process. I thought this was a forum for helping ppl not flaming them - I think you need to read what YOU wrote as YOUR loop test! HTH (If this comment was disrespectful, please report it.)
I just get pissed when i c ppl who don't even know what they r saying posting comments saying something is wrong, i wrote this code in the momment i saw the post about that guy answering to yer other post. I didn't even test it it is just obvious what he code would do. Laterz (If this comment was disrespectful, please report it.)
LOL, this stuff is funny, i thought this was a place for coders, but i see also humorists are welcome. By the way, $x starts at 0, then it checks if $x is below or equal to 100, then adds 1. Since it is is a for loop it won't continue executing the code inside the loop when $x is greater then 100, it will however add 1 to $x AFTER the the max is reached, so it will come to a total of 101, not loops, but $x. if you dont understand, check it with the following code:
#! /usr/bin/perl -w
for ($x = 0; $x <= 100; $x++ ) {
print (If this comment was disrespectful, please report it.)
Yah, this code is ignorant. Anbody who knows Perl knows how to do a simple loop such as this one...ugh! Post something worth reading and viewing ;-) Oh, btw, check out my site Synthesize VB. We have alot of VB stuff but the whole site is based off Perl so if you wanna see a website with some Perl action, then scope this site. Thanx (If this comment was disrespectful, please report it.)
Hey James! I didn't know that you were a member here! Please, everyone, check out our site!!! It is Perl-based, like James said. I did most of it, but I am letting James do a bit here and there. It is a good start, but we need to get all of the pages up! Bye! (If this comment was disrespectful, please report it.)
I think what confuses most programmers is the fact it says ;$x<=100; when you are thinking in your head "when $x>=100 then stop". The logic of the "for" loop is actually "so long as $x<=100, then keep going". The fact the author forget his ending } is irrelevent since you know to do this anyway. (If this comment was disrespectful, please report it.)
i thought i was gonna find a big tutorial... i found an incomplete for loop :) (If this comment was disrespectful, please report it.)
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By 12 Users
1/31/2001 6:16:15 PM: 
