SQL Server 7.0, SQL Server 6.5 and earlier, Informix
, Oracle, Other
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Determine the product of values in a column.
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--**************************************
-- Name: Compute product of values
-- Description:Determine the product of values in a column.
-- By: Umachandar
--
--This code is copyrighted and has-- limited warranties.Please see http://www.Planet-Source-Code.com/vb/scripts/ShowCode.asp?txtCodeId=159&lngWId=5--for details.--**************************************
create table #tbltest (value numeric(3,1))
insert #tblTest values(-1.5)
insert #tblTest values(1.5)
insert #tblTest values(2.5)
insert #tblTest values(0)
select * from #tbltest
select case sum(case when sign(value) = -1 then 1 else 0 end)%2 when 1 then -1 else 1 end
* exp(sum(log(abs(case when sign(value) <> 0 then value end))))
* min(case when value = 0 then 0 else 1 end) as Prod1,
case when sum(case when sign(value) = -1 then 1 end) > 0 then -1 else 1 end
* exp(sum(log(abs(case when sign(value) <> 0 then value end))))
* min(case when value = 0 then 0 else 1 end) as Prod2
from #tblTest
delete #tbltest where value = 0
select case sum(case when sign(value) = -1 then 1 else 0 end)%2 when 1 then -1 else 1 end
* exp(sum(log(abs(case when sign(value) <> 0 then value end))))
* min(case when value = 0 then 0 else 1 end) as Prod1,
case when sum(case when sign(value) = -1 then 1 end) > 0 then -1 else 1 end
* exp(sum(log(abs(case when sign(value) <> 0 then value end))))
* min(case when value = 0 then 0 else 1 end) as Prod2
from #tblTest
delete #tbltest where sign(value) = -1
select case sum(case when sign(value) = -1 then 1 else 0 end)%2 when 1 then -1 else 1 end
* exp(sum(log(abs(case when sign(value) <> 0 then value end))))
* min(case when value = 0 then 0 else 1 end) as Prod1,
case when sum(case when sign(value) = -1 then 1 end) > 0 then -1 else 1 end
* exp(sum(log(abs(case when sign(value) <> 0 then value end))))
* min(case when value = 0 then 0 else 1 end) as Prod2
from #tblTest
Brill! just what i needed (If this comment was disrespectful, please report it.)
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By 2 Users
5/23/2002 6:04:51 PM: 
