List a Number Without Using a Loop in C++

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 Submitted on: 10/20/2016 1:21:01 AM By: Jake R. Pomperada Level: Beginner User Rating: Unrated Compatibility: C++ (general) Views: 3023

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 ``` //************************************** // Name: List a Number Without Using a Loop in C++ // Description: Thursday, October 20, 2016 Grading System Using Pointers in C++ Here is another C++ program that I wrote a very long time ago using Pointers that will ask the users grade and then our program will check if the user pass or failed in a particular subject. The code is very easy to understand and use. I hope you will find my work useful. Thank you. Add me at Facebook my address is jakerpomperada@gmail.com and jakerpomperada@yahoo.com. My email address are the following jakerpomperada@gmail.com and jakerpomperada@yahoo.com. My mobile number here in the Philippines is 09173084360. Program Listing #include using namespace std; main() { int array[10]; int *p; p = array; cout << "\t Grade Selector 1.0"; cout << "\n\n"; for (int a=0; a<10; a++) { cout << "\nEnter Grade No. " << a+1 << ":"; cin >> p[a]; } cout << "\n\n"; cout << "\nGrade 90 To 100"; cout << "\n"; for (int a=0; a<10; a++) { if (p[a] >= 90 && p[a] <=100) { cout << "\n" <= 80 && p[a] <=89) { cout << "\n" <= 75 && p[a] <=79) { cout << "\n" < #include using namespace std; int print(int num){ if(num<=50){ cout << " " << num << " "; print(num+1); } } int main(){ int num = 1; cout << "\nList of Numbers Without Using a Loop in C++"; cout <<"\n\n"; print(num); cout <<"\n\n"; cout << "\nEnd of Program"; cout <<"\n\n"; system("pause"); } ```

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