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List a Number Without Using a Loop in C++

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Submitted on: 10/20/2016 1:21:01 AM
By: Jake R. Pomperada  
Level: Beginner
User Rating: Unrated
Compatibility: C++ (general)
Views: 1165
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      Thursday, October 20, 2016 Grading System Using Pointers in C++ Here is another C++ program that I wrote a very long time ago using Pointers that will ask the users grade and then our program will check if the user pass or failed in a particular subject. The code is very easy to understand and use. I hope you will find my work useful. Thank you. Add me at Facebook my address is jakerpomperada@gmail.com and jakerpomperada@yahoo.com. My email address are the following jakerpomperada@gmail.com and jakerpomperada@yahoo.com. My mobile number here in the Philippines is 09173084360. Program Listing #include using namespace std; main() { int array[10]; int *p; p = array; cout << "\t Grade Selector 1.0"; cout << "\n\n"; for (int a=0; a<10; a++) { cout << "\nEnter Grade No. " << a+1 << ":"; cin >> p[a]; } cout << "\n\n"; cout << "\nGrade 90 To 100"; cout << "\n"; for (int a=0; a<10; a++) { if (p[a] >= 90 && p[a] <=100) { cout << "\n" <= 80 && p[a] <=89) { cout << "\n" <= 75 && p[a] <=79) { cout << "\n" <
 
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//**************************************
// Name: List a Number Without Using a Loop in C++
// Description:
Thursday, October 20, 2016
Grading System Using Pointers in C++
Here is another C++ program that I wrote a very long time ago using Pointers that will ask the users grade and then our program will check if the user pass or failed in a particular subject. The code is very easy to understand and use. I hope you will find my work useful. Thank you.
Add me at Facebook my address is jakerpomperada@gmail.com and jakerpomperada@yahoo.com. 
My email address are the following jakerpomperada@gmail.com and jakerpomperada@yahoo.com. 
My mobile number here in the Philippines is 09173084360.
Program Listing
#include <iostream>
using namespace std;
main() {
int array[10];
int *p;
p = array;
cout << "\t Grade Selector 1.0";
cout << "\n\n";
for (int a=0; a<10; a++)
 {
 cout << "\nEnter Grade No. " << a+1 << ":";
 cin >> p[a];
 }
 cout << "\n\n";
 cout << "\nGrade 90 To 100";
 cout << "\n";
 for (int a=0; a<10; a++)
 {
if (p[a] >= 90 && p[a] <=100) {
cout << "\n" <<p[a];
}
 }
 cout << "\n\n";
 cout << "\nGrade 80 To 89";
 cout << "\n";
 for (int a=0; a<10; a++)
 {
if (p[a] >= 80 && p[a] <=89) {
cout << "\n" <<p[a];
}
 }
 cout << "\n\n";
 cout << "\nGrade 75 To 79";
 cout << "\n";
 for (int a=0; a<10; a++)
 {
if (p[a] >= 75 && p[a] <=79) {
cout << "\n" <<p[a];
}
 }
 cout << "\n\n";
 cout << "\nList of Failing Grades";
 cout << "\n";
 for (int a=0; a<10; a++)
 {
if (p[a] < 75) {
cout << "\n" <<p[a];
}
 }
 cout << "\n\n";
 system("pause");
}
Posted by Jake Pomperada at 9:17 AM No comments: 
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Labels: grade selector using pointers in c++, grading system using pointers in c++
List a Number Without Using a Loop in C++
Here is a code that I wrote a very long time ago that will list a number from 1 to 50 without using any looping statement in C++ but rather it uses if statement.
Add me at Facebook my address is jakerpomperada@gmail.com and jakerpomperada@yahoo.com. 
My email address are the following jakerpomperada@gmail.com and jakerpomperada@yahoo.com. 
My mobile number here in the Philippines is 09173084360.
// By: Jake R. Pomperada
//**************************************

#include <iostream>
#include <stdlib.h>
using namespace std;
int print(int num){
if(num<=50){
 cout << " " << num << " ";
 print(num+1);
}
}
int main(){
int num = 1;
cout << "\nList of Numbers Without Using a Loop in C++";
cout <<"\n\n";
print(num);
cout <<"\n\n";
cout << "\nEnd of Program";
cout <<"\n\n";
system("pause");
}


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