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Parse A Comma Delimited String Function

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Submitted on: 11/14/2006 12:52:39 PM
By: Dave Vroman 
Level: Beginner
User Rating: By 6 Users
Compatibility: SQL Server 2000
Views: 24015
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     This Routine Returns All Of The Data From A Comma Delimited String Into A Table.
A Simple Test Is:
SELECT * FROM dbo.ParseByComma('1,2,3,4,5,6,7,8')

 
 
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				/*********************************************************
** Parse A Comma Delimited String Into A Table
** Description: When A Web Page Sends An Array Of Data To
** The Server, The Array Is Comma Delimited.
** This Routine Returns All Of The Data From A Comma
** Delimited String Into A Table.
**
** By: Dave Vroman
*********************************************************/

CREATE FUNCTION dbo.ParseByComma ( @String VARCHAR(600) )
RETURNS @TblSubString TABLE
(
VarSubString VARCHAR(10)
)
AS
BEGIN
DECLARE @intPos INT,
@SubStr VARCHAR(10)
-- Remove All Spaces
SET @String = REPLACE(@String, ' ','')
-- Find The First Comma
SET @IntPos = CHARINDEX(',', @String)
-- Loop Until There Is Nothing Left Of @String
WHILE @IntPos > 0
BEGIN
-- Extract The String
SET @SubStr = SUBSTRING(@String, 0, @IntPos)
-- Insert The String Into The Table
INSERT INTO @TblSubString (VarSubString) VALUES (@SubStr)
-- Remove The String & Comma Separator From The Original
SET @String = SUBSTRING(@String, LEN(@SubStr) + 2, LEN(@String) - LEN(@SubStr) + 1)
-- Get The New Index To The String
SET @IntPos = CHARINDEX(',', @String)
END
-- Return The Last One
INSERT INTO @TblSubString (VarSubString) VALUES (@String)
RETURN
END


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Other User Comments
11/12/2006 2:29:52 PMJeff Moden

You appear to have a bit of an oversite in your function... try this to see what I mean...

SELECT * FROM dbo.ParseByComma('1,2,3,3,3,3,4,5,6,7,8')
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11/13/2006 9:21:11 AMJeff Moden

I wasn't going to vote until the author of the code fixed a bug I highlited in my previous message. But, since someone else voted a high vote on this code that produces unexpected results in the face of duplication, I had to vote pretty low because the code does not work as advertised. Sorry...
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11/13/2006 11:22:34 AMDave Vroman

This is not an error or bug. The "fix" for you is to use "SELECT DISTINCT" which is very standard in SQL. Putting the "DISTINCT" code in the routine would introduce possible unintended errors.
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11/13/2006 7:21:20 PMJeff Moden

And what if the number 3 is actually required more than once for the different parameters... DISTINCT is going to do anything except make sure that I don't get what I want. The function does not return all of the parameters I pass it. That's a bug.
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11/14/2006 3:01:34 PMDave Vroman

try it now
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11/14/2006 11:30:59 PMChris

Jeff is correct. This function is flawed and although it might suite your implmentation it could hurt alot of other unweiry people.
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11/16/2006 8:47:13 PMJeff Moden

Much better! I tried real hard to break it and couldn't. I even tried the following "ACE" breakers...

SELECT *
FROM dbo.ParseByComma(',1,,,,2,')

SELECT *
FROM dbo.ParseByComma('')

SELECT *
FROM dbo.ParseByComma(NULL)

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11/16/2006 8:50:23 PMJeff Moden

p.s. It's kinda cool that this forum let's me change my vote... I changed it from a 1 to a 5 not only because of the correction Dave made, but because he also included embedded comments for clarification. Nicely done, Dave.
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11/16/2006 8:51:43 PMJeff Moden

AND... because Dave actually took the time to make a correction to his code, I encourage you to vote on this code, as well.
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9/12/2007 12:08:18 PMDavid

I don't understand why this works:

SELECT users.lname, users.practice
FROM users WHERE practice IN (SELECT * FROM dbo.ufn_ParseByComma( '110,1,2' ));

And this doesn't:

SELECT users.lname, users.practice
FROM users WHERE practice IN (SELECT * FROM dbo.ufn_ParseByComma( users.practice ));

users.practice is a string. What am I missing?
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